Hi,
I have a project that deals with a horizontal cylindrical tank in labview and I am trying to figure out a few things.
1) The example model in labview uses the equation: dh/dt = (qi - Cv*sqrt(h)) / (2*L*sqrt((D-h)^2)) where: qi is flow in, h is height of fluid level, D is diameter of tank and L is the length.
Now I understand this is of the form, dh/dt = (qi - k*sqrt(h))/ (A)
Going based off of examples found from places such as example of a conical tank for modelling,
I do not understand where the form of 2*L fits into the equation for cross sectional area of the horizontal cylindrical tank.
Any assistance would be appreciated.